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11006506301403 = 319210162979041
BaseRepresentation
bin1010000000101010011011…
…1001011111011111011011
31102222012201100102000221110
42200022212321133133123
52420312311103121103
635224152540111403
72214123325632144
oct240124671373733
942865640360843
1011006506301403
113563918960508
121299174835563
1361aba8370142
142a0a096daacb
151414879a2403
hexa02a6e5f7db

11006506301403 has 12 divisors (see below), whose sum is σ = 15488380060008. Its totient is φ = 6951477663360.

The previous prime is 11006506301393. The next prime is 11006506301429. The reversal of 11006506301403 is 30410360560011.

It is not a de Polignac number, because 11006506301403 - 26 = 11006506301339 is a prime.

It is a super-3 number, since 3×110065063014033 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (11006506301803) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5081488438 + ... + 5081490603.

It is an arithmetic number, because the mean of its divisors is an integer number (1290698338334).

Almost surely, 211006506301403 is an apocalyptic number.

11006506301403 is a deficient number, since it is larger than the sum of its proper divisors (4481873758605).

11006506301403 is a wasteful number, since it uses less digits than its factorization.

11006506301403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10162979082 (or 10162979063 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 11006506301403 its reverse (30410360560011), we get a palindrome (41416866861414).

The spelling of 11006506301403 in words is "eleven trillion, six billion, five hundred six million, three hundred one thousand, four hundred three".

Divisors: 1 3 19 57 361 1083 10162979041 30488937123 193096601779 579289805337 3668835433801 11006506301403