Base | Representation |
---|---|
bin | 1010000000101010011100… |
… | …1000100001110100111110 |
3 | 1102222012201121211021222111 |
4 | 2200022213020201310332 |
5 | 2420312313110240014 |
6 | 35224153200404234 |
7 | 2214123404300110 |
oct | 240124710416476 |
9 | 42865647737874 |
10 | 11006510243134 |
11 | 3563920102a3a |
12 | 129917601667a |
13 | 61aba9120323 |
14 | 2a0a0a0453b0 |
15 | 141487ed02c4 |
hex | a02a7221d3e |
11006510243134 has 16 divisors (see below), whose sum is σ = 18927824743008. Its totient is φ = 4702195451232.
The previous prime is 11006510243123. The next prime is 11006510243173. The reversal of 11006510243134 is 43134201560011.
It is a super-2 number, since 2×110065102431342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11006510243096 and 11006510243105.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1240026009 + ... + 1240034884.
It is an arithmetic number, because the mean of its divisors is an integer number (1182989046438).
Almost surely, 211006510243134 is an apocalyptic number.
11006510243134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
11006510243134 is a deficient number, since it is larger than the sum of its proper divisors (7921314499874).
11006510243134 is a wasteful number, since it uses less digits than its factorization.
11006510243134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2480061219.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 11006510243134 in words is "eleven trillion, six billion, five hundred ten million, two hundred forty-three thousand, one hundred thirty-four".
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