Base | Representation |
---|---|
bin | 110011010000001110… |
… | …1101110011000111011 |
3 | 101112002201012211212011 |
4 | 1212200131232120323 |
5 | 3300403440013042 |
6 | 122321435230351 |
7 | 10644355234615 |
oct | 1464035563073 |
9 | 345081184764 |
10 | 110066329147 |
11 | 42751634195 |
12 | 193b8ba83b7 |
13 | a4c1181918 |
14 | 5481d2bdb5 |
15 | 2ce2d4aa17 |
hex | 19a076e63b |
110066329147 has 2 divisors, whose sum is σ = 110066329148. Its totient is φ = 110066329146.
The previous prime is 110066328991. The next prime is 110066329151. The reversal of 110066329147 is 741923660011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110066329147 is a prime.
It is a super-2 number, since 2×1100663291472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110066309147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55033164573 + 55033164574.
It is an arithmetic number, because the mean of its divisors is an integer number (55033164574).
Almost surely, 2110066329147 is an apocalyptic number.
110066329147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110066329147 is an equidigital number, since it uses as much as digits as its factorization.
110066329147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 40.
Adding to 110066329147 its reverse (741923660011), we get a palindrome (851989989158).
The spelling of 110066329147 in words is "one hundred ten billion, sixty-six million, three hundred twenty-nine thousand, one hundred forty-seven".
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