Search a number
-
+
110100100110131 is a prime number
BaseRepresentation
bin11001000010001010101101…
…010110110101011100110011
3112102211110121021120020122102
4121002022231112311130303
5103412340001112011011
61030055142052331015
732122320055436405
oct3102125526653463
9472743537506572
10110100100110131
113209921023253a
1210422178913a6b
134958519762861
141d28c323c0b75
15cade5262473b
hex6422ad5b5733

110100100110131 has 2 divisors, whose sum is σ = 110100100110132. Its totient is φ = 110100100110130.

The previous prime is 110100100110101. The next prime is 110100100110137. The reversal of 110100100110131 is 131011001001011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110100100110131 - 234 = 110082920240947 is a prime.

It is a super-2 number, since 2×1101001001101312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110100100110137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050050055065 + 55050050055066.

It is an arithmetic number, because the mean of its divisors is an integer number (55050050055066).

Almost surely, 2110100100110131 is an apocalyptic number.

110100100110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

110100100110131 is an equidigital number, since it uses as much as digits as its factorization.

110100100110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 110100100110131 its reverse (131011001001011), we get a palindrome (241111101111142).

The spelling of 110100100110131 in words is "one hundred ten trillion, one hundred billion, one hundred million, one hundred ten thousand, one hundred thirty-one".