Base | Representation |
---|---|
bin | 10000000001011000110… |
… | …010011000101010011011 |
3 | 10220020212200001120110111 |
4 | 100001120302120222123 |
5 | 121014322303343003 |
6 | 2201443141225151 |
7 | 142354560023242 |
oct | 20013062305233 |
9 | 3806780046414 |
10 | 1101001231003 |
11 | 394a28545733 |
12 | 15946b1021b7 |
13 | 7ca9335685b |
14 | 3b408455959 |
15 | 1d98d826e6d |
hex | 10058c98a9b |
1101001231003 has 2 divisors, whose sum is σ = 1101001231004. Its totient is φ = 1101001231002.
The previous prime is 1101001230991. The next prime is 1101001231021. The reversal of 1101001231003 is 3001321001011.
It is a weak prime.
It is an emirp because it is prime and its reverse (3001321001011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1101001231003 - 217 = 1101001099931 is a prime.
It is a super-3 number, since 3×11010012310033 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1101001231703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550500615501 + 550500615502.
It is an arithmetic number, because the mean of its divisors is an integer number (550500615502).
Almost surely, 21101001231003 is an apocalyptic number.
1101001231003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101001231003 is an equidigital number, since it uses as much as digits as its factorization.
1101001231003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1101001231003 its reverse (3001321001011), we get a palindrome (4102322232014).
The spelling of 1101001231003 in words is "one trillion, one hundred one billion, one million, two hundred thirty-one thousand, three".
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