Base | Representation |
---|---|
bin | 10000000001011000110… |
… | …010101110011101000001 |
3 | 10220020212200020002220012 |
4 | 100001120302232131001 |
5 | 121014322314222012 |
6 | 2201443143154305 |
7 | 142354560544406 |
oct | 20013062563501 |
9 | 3806780202805 |
10 | 1101001320257 |
11 | 394a285a67a3 |
12 | 15946b145995 |
13 | 7ca93388377 |
14 | 3b40847a2ad |
15 | 1d98d843622 |
hex | 10058cae741 |
1101001320257 has 2 divisors, whose sum is σ = 1101001320258. Its totient is φ = 1101001320256.
The previous prime is 1101001320247. The next prime is 1101001320361. The reversal of 1101001320257 is 7520231001011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 653374755856 + 447626564401 = 808316^2 + 669049^2 .
It is an emirp because it is prime and its reverse (7520231001011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1101001320257 - 220 = 1101000271681 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101001320227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550500660128 + 550500660129.
It is an arithmetic number, because the mean of its divisors is an integer number (550500660129).
Almost surely, 21101001320257 is an apocalyptic number.
It is an amenable number.
1101001320257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101001320257 is an equidigital number, since it uses as much as digits as its factorization.
1101001320257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 23.
Adding to 1101001320257 its reverse (7520231001011), we get a palindrome (8621232321268).
The spelling of 1101001320257 in words is "one trillion, one hundred one billion, one million, three hundred twenty thousand, two hundred fifty-seven".
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