Base | Representation |
---|---|
bin | 1010000000110111110100… |
… | …1011000001001100010001 |
3 | 1102222112222212212211022212 |
4 | 2200031331023001030101 |
5 | 2420342141403020423 |
6 | 35225545355441505 |
7 | 2214311400141542 |
oct | 240157513011421 |
9 | 42875885784285 |
10 | 11010101220113 |
11 | 35653a3119106 |
12 | 12999b8756295 |
13 | 61b32c091488 |
14 | 2a0c6ad264c9 |
15 | 1415e83ad578 |
hex | a037d2c1311 |
11010101220113 has 2 divisors, whose sum is σ = 11010101220114. Its totient is φ = 11010101220112.
The previous prime is 11010101220103. The next prime is 11010101220137. The reversal of 11010101220113 is 31102210101011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5564258241424 + 5445842978689 = 2358868^2 + 2333633^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11010101220113 is a prime.
It is a super-3 number, since 3×110101012201133 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11010101220103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505050610056 + 5505050610057.
It is an arithmetic number, because the mean of its divisors is an integer number (5505050610057).
Almost surely, 211010101220113 is an apocalyptic number.
It is an amenable number.
11010101220113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010101220113 is an equidigital number, since it uses as much as digits as its factorization.
11010101220113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 11010101220113 its reverse (31102210101011), we get a palindrome (42112311321124).
The spelling of 11010101220113 in words is "eleven trillion, ten billion, one hundred one million, two hundred twenty thousand, one hundred thirteen".
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