1101012113 has 4 divisors (see below), whose sum is σ = 1101310320. Its totient is φ = 1100713908.

The previous prime is 1101012109. The next prime is 1101012127. The reversal of 1101012113 is 3112101011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112101011 = 53 ⋅58718887.

It is a cyclic number.

It is not a de Polignac number, because 1101012113 - 2² = 1101012109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1101012094 and 1101012103.

It is not an unprimeable number, because it can be changed into a prime (1101012103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143495 + ... + 150972.

It is an arithmetic number, because the mean of its divisors is an integer number (275327580).

Almost surely, 2^1101012113 is an apocalyptic number.

It is an amenable number.

1101012113 is a deficient number, since it is larger than the sum of its proper divisors (298207).

1101012113 is an equidigital number, since it uses as much as digits as its factorization.

1101012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 298206.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 1101012113 is about 33181.5025729698. The cubic root of 1101012113 is about 1032.5966196539.

Adding to 1101012113 its reverse (3112101011), we get a palindrome (4213113124).

The spelling of 1101012113 in words is "one billion, one hundred one million, twelve thousand, one hundred thirteen".