Base | Representation |
---|---|
bin | 1010000000110111111111… |
… | …0010001110100111101001 |
3 | 1102222120002221100202222002 |
4 | 2200031333302032213221 |
5 | 2420342234113200121 |
6 | 35225554003140345 |
7 | 2214312441542642 |
oct | 240157762164751 |
9 | 42876087322862 |
10 | 11010145053161 |
11 | 3565415937571 |
12 | 1299a0b3746b5 |
13 | 61b33819a8a7 |
14 | 2a0c72a966c9 |
15 | 1415ec16ae0b |
hex | a037fc8e9e9 |
11010145053161 has 2 divisors, whose sum is σ = 11010145053162. Its totient is φ = 11010145053160.
The previous prime is 11010145053157. The next prime is 11010145053197. The reversal of 11010145053161 is 16135054101011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10936910410000 + 73234643161 = 3307100^2 + 270619^2 .
It is a cyclic number.
It is not a de Polignac number, because 11010145053161 - 22 = 11010145053157 is a prime.
It is not a weakly prime, because it can be changed into another prime (11010145053461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505072526580 + 5505072526581.
It is an arithmetic number, because the mean of its divisors is an integer number (5505072526581).
Almost surely, 211010145053161 is an apocalyptic number.
It is an amenable number.
11010145053161 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010145053161 is an equidigital number, since it uses as much as digits as its factorization.
11010145053161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 29.
Adding to 11010145053161 its reverse (16135054101011), we get a palindrome (27145199154172).
The spelling of 11010145053161 in words is "eleven trillion, ten billion, one hundred forty-five million, fifty-three thousand, one hundred sixty-one".
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