Base | Representation |
---|---|
bin | 10000000001011010000… |
… | …010000100100010111011 |
3 | 10220020221010100211221121 |
4 | 100001122002010202323 |
5 | 121014343130320443 |
6 | 2201445205050111 |
7 | 142355232414412 |
oct | 20013202044273 |
9 | 3806833324847 |
10 | 1101022120123 |
11 | 394a39312a72 |
12 | 1594760b6937 |
13 | 7ca9778b893 |
14 | 3b40b132479 |
15 | 1d9905a14ed |
hex | 1005a0848bb |
1101022120123 has 2 divisors, whose sum is σ = 1101022120124. Its totient is φ = 1101022120122.
The previous prime is 1101022120067. The next prime is 1101022120157. The reversal of 1101022120123 is 3210212201011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1101022120123 - 217 = 1101021989051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1101022120097 and 1101022120106.
It is not a weakly prime, because it can be changed into another prime (1101022120193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550511060061 + 550511060062.
It is an arithmetic number, because the mean of its divisors is an integer number (550511060062).
Almost surely, 21101022120123 is an apocalyptic number.
1101022120123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101022120123 is an equidigital number, since it uses as much as digits as its factorization.
1101022120123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1101022120123 its reverse (3210212201011), we get a palindrome (4311234321134).
The spelling of 1101022120123 in words is "one trillion, one hundred one billion, twenty-two million, one hundred twenty thousand, one hundred twenty-three".
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