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11010424410113 is a prime number
BaseRepresentation
bin1010000000111001000001…
…1011111001000000000001
31102222120211102000120122212
42200032100123321000001
52420343322122110423
635230041422511505
72214322403204462
oct240162033710001
942876742016585
1011010424410113
1135655495a1587
121299a88a35595
1361b38101b66b
142a0c9bc14d69
1514161694d578
hexa03906f9001

11010424410113 has 2 divisors, whose sum is σ = 11010424410114. Its totient is φ = 11010424410112.

The previous prime is 11010424410103. The next prime is 11010424410127. The reversal of 11010424410113 is 31101442401011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7647392913664 + 3363031496449 = 2765392^2 + 1833857^2 .

It is an emirp because it is prime and its reverse (31101442401011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11010424410113 - 214 = 11010424393729 is a prime.

It is not a weakly prime, because it can be changed into another prime (11010424410103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505212205056 + 5505212205057.

It is an arithmetic number, because the mean of its divisors is an integer number (5505212205057).

Almost surely, 211010424410113 is an apocalyptic number.

It is an amenable number.

11010424410113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010424410113 is an equidigital number, since it uses as much as digits as its factorization.

11010424410113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 11010424410113 its reverse (31101442401011), we get a palindrome (42111866811124).

It can be divided in two parts, 1101042 and 4410113, that added together give a palindrome (5511155).

The spelling of 11010424410113 in words is "eleven trillion, ten billion, four hundred twenty-four million, four hundred ten thousand, one hundred thirteen".