Base | Representation |
---|---|
bin | 110011010001100010… |
… | …0010100001110110111 |
3 | 101112012202101120002012 |
4 | 1212203010110032313 |
5 | 3301001130000210 |
6 | 122330035234435 |
7 | 10645425362216 |
oct | 1464304241667 |
9 | 345182346065 |
10 | 110110000055 |
11 | 42774251850 |
12 | 1940b748a1b |
13 | a4ca2322b3 |
14 | 5487a5907d |
15 | 2ce6ac5305 |
hex | 19a31143b7 |
110110000055 has 16 divisors (see below), whose sum is σ = 144890874144. Its totient is φ = 79665070080.
The previous prime is 110110000043. The next prime is 110110000067. The reversal of 110110000055 is 550000011011.
It is an interprime number because it is at equal distance from previous prime (110110000043) and next prime (110110000067).
It is not a de Polignac number, because 110110000055 - 224 = 110093222839 is a prime.
It is a super-2 number, since 2×1101100000552 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110109999994 and 110110000039.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5175914 + ... + 5197143.
It is an arithmetic number, because the mean of its divisors is an integer number (9055679634).
Almost surely, 2110110000055 is an apocalyptic number.
110110000055 is a deficient number, since it is larger than the sum of its proper divisors (34780874089).
110110000055 is a wasteful number, since it uses less digits than its factorization.
110110000055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10373266.
The product of its (nonzero) digits is 25, while the sum is 14.
Adding to 110110000055 its reverse (550000011011), we get a palindrome (660110011066).
The spelling of 110110000055 in words is "one hundred ten billion, one hundred ten million, fifty-five", and thus it is an aban number.
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