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11011011307 is a prime number
BaseRepresentation
bin10100100000100111…
…01011001011101011
31001102101011022220121
422100103223023223
5140022304330212
65020340104111
7536602023532
oct122023531353
931371138817
1011011011307
11474047984a
122173695037
1310662b160a
14766539319
15446a16d07
hex2904eb2eb

11011011307 has 2 divisors, whose sum is σ = 11011011308. Its totient is φ = 11011011306.

The previous prime is 11011011289. The next prime is 11011011353. The reversal of 11011011307 is 70311011011.

11011011307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (70311011011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11011011307 is a prime.

It is not a weakly prime, because it can be changed into another prime (11011071307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505505653 + 5505505654.

It is an arithmetic number, because the mean of its divisors is an integer number (5505505654).

Almost surely, 211011011307 is an apocalyptic number.

11011011307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011011307 is an equidigital number, since it uses as much as digits as its factorization.

11011011307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21, while the sum is 16.

Adding to 11011011307 its reverse (70311011011), we get a palindrome (81322022318).

The spelling of 11011011307 in words is "eleven billion, eleven million, eleven thousand, three hundred seven".