Base | Representation |
---|---|
bin | 11001000010010100000111… |
… | …010111101100100111011011 |
3 | 112102212102200011200222212021 |
4 | 121002110013113230213123 |
5 | 103413021142224020443 |
6 | 1030103532212555311 |
7 | 32123125260112255 |
oct | 3102240727544733 |
9 | 472772604628767 |
10 | 110110200220123 |
11 | 320a2523503684 |
12 | 10424117322b37 |
13 | 49594691018bc |
14 | 1d2950d962cd5 |
15 | cae3441a99ed |
hex | 6425075ec9db |
110110200220123 has 2 divisors, whose sum is σ = 110110200220124. Its totient is φ = 110110200220122.
The previous prime is 110110200220061. The next prime is 110110200220151. The reversal of 110110200220123 is 321022002011011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110110200220123 - 233 = 110101610285531 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110110200220097 and 110110200220106.
It is not a weakly prime, because it can be changed into another prime (110110200220183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055100110061 + 55055100110062.
It is an arithmetic number, because the mean of its divisors is an integer number (55055100110062).
Almost surely, 2110110200220123 is an apocalyptic number.
110110200220123 is a deficient number, since it is larger than the sum of its proper divisors (1).
110110200220123 is an equidigital number, since it uses as much as digits as its factorization.
110110200220123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 110110200220123 its reverse (321022002011011), we get a palindrome (431132202231134).
The spelling of 110110200220123 in words is "one hundred ten trillion, one hundred ten billion, two hundred million, two hundred twenty thousand, one hundred twenty-three".
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