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110110200220123 is a prime number
BaseRepresentation
bin11001000010010100000111…
…010111101100100111011011
3112102212102200011200222212021
4121002110013113230213123
5103413021142224020443
61030103532212555311
732123125260112255
oct3102240727544733
9472772604628767
10110110200220123
11320a2523503684
1210424117322b37
1349594691018bc
141d2950d962cd5
15cae3441a99ed
hex6425075ec9db

110110200220123 has 2 divisors, whose sum is σ = 110110200220124. Its totient is φ = 110110200220122.

The previous prime is 110110200220061. The next prime is 110110200220151. The reversal of 110110200220123 is 321022002011011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110110200220123 - 233 = 110101610285531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110110200220097 and 110110200220106.

It is not a weakly prime, because it can be changed into another prime (110110200220183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055100110061 + 55055100110062.

It is an arithmetic number, because the mean of its divisors is an integer number (55055100110062).

Almost surely, 2110110200220123 is an apocalyptic number.

110110200220123 is a deficient number, since it is larger than the sum of its proper divisors (1).

110110200220123 is an equidigital number, since it uses as much as digits as its factorization.

110110200220123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 110110200220123 its reverse (321022002011011), we get a palindrome (431132202231134).

The spelling of 110110200220123 in words is "one hundred ten trillion, one hundred ten billion, two hundred million, two hundred twenty thousand, one hundred twenty-three".