Base | Representation |
---|---|
bin | 1010000000111011010000… |
… | …0011100000111110110011 |
3 | 1102222122101001111021221112 |
4 | 2200032310003200332303 |
5 | 2420401033113000201 |
6 | 35230221011143535 |
7 | 2214343250505263 |
oct | 240166403407663 |
9 | 42878331437845 |
10 | 11011022000051 |
11 | 3565825953767 |
12 | 129a014ba4bab |
13 | 61b447a82288 |
14 | 2a0d173317a3 |
15 | 14164e1420bb |
hex | a03b40e0fb3 |
11011022000051 has 2 divisors, whose sum is σ = 11011022000052. Its totient is φ = 11011022000050.
The previous prime is 11011021999981. The next prime is 11011022000059. The reversal of 11011022000051 is 15000022011011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11011022000051 is a prime.
It is not a weakly prime, because it can be changed into another prime (11011022000059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505511000025 + 5505511000026.
It is an arithmetic number, because the mean of its divisors is an integer number (5505511000026).
Almost surely, 211011022000051 is an apocalyptic number.
11011022000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011022000051 is an equidigital number, since it uses as much as digits as its factorization.
11011022000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 11011022000051 its reverse (15000022011011), we get a palindrome (26011044011062).
The spelling of 11011022000051 in words is "eleven trillion, eleven billion, twenty-two million, fifty-one", and thus it is an aban number and an uban number.
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