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11011033901137 is a prime number
BaseRepresentation
bin1010000000111011010011…
…0000111010100001010001
31102222122101212212221011111
42200032310300322201101
52420401044134314022
635230222114213321
72214343453613314
oct240166460724121
942878355787144
1011011033901137
113565831642176
12129a018b84241
1361b44a38b23a
142a0d18b4c97b
151416501e3477
hexa03b4c3a851

11011033901137 has 2 divisors, whose sum is σ = 11011033901138. Its totient is φ = 11011033901136.

The previous prime is 11011033901069. The next prime is 11011033901141. The reversal of 11011033901137 is 73110933011011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6114744785601 + 4896289115536 = 2472801^2 + 2212756^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11011033901137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11011033901099 and 11011033901108.

It is not a weakly prime, because it can be changed into another prime (11011033901237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505516950568 + 5505516950569.

It is an arithmetic number, because the mean of its divisors is an integer number (5505516950569).

Almost surely, 211011033901137 is an apocalyptic number.

It is an amenable number.

11011033901137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011033901137 is an equidigital number, since it uses as much as digits as its factorization.

11011033901137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1701, while the sum is 31.

Adding to 11011033901137 its reverse (73110933011011), we get a palindrome (84121966912148).

The spelling of 11011033901137 in words is "eleven trillion, eleven billion, thirty-three million, nine hundred one thousand, one hundred thirty-seven".