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1101110012113 is a prime number
BaseRepresentation
bin10000000001011111010…
…001010110100011010001
310220021011020202020002111
4100001133101112203101
5121020033130341423
62201502024545321
7142360350450316
oct20013721264321
93807136666074
101101110012113
11394a83994581
1215949b622241
137caaca53187
143b418a90d0d
151d99816360d
hex1005f4568d1

1101110012113 has 2 divisors, whose sum is σ = 1101110012114. Its totient is φ = 1101110012112.

The previous prime is 1101110012083. The next prime is 1101110012129. The reversal of 1101110012113 is 3112100111011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1078226794129 + 22883217984 = 1038377^2 + 151272^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101110012113 - 229 = 1100573141201 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1101110012093 and 1101110012102.

It is not a weakly prime, because it can be changed into another prime (1101110012713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550555006056 + 550555006057.

It is an arithmetic number, because the mean of its divisors is an integer number (550555006057).

Almost surely, 21101110012113 is an apocalyptic number.

It is an amenable number.

1101110012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101110012113 is an equidigital number, since it uses as much as digits as its factorization.

1101110012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1101110012113 its reverse (3112100111011), we get a palindrome (4213210123124).

The spelling of 1101110012113 in words is "one trillion, one hundred one billion, one hundred ten million, twelve thousand, one hundred thirteen".