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110111010011081 is a prime number
BaseRepresentation
bin11001000010010100110111…
…101000110011011111001001
3112102212111202121110122012222
4121002110313220303133021
5103413024322030323311
61030104144421343425
732123154322164662
oct3102246750633711
9472774677418188
10110111010011081
11320a28a9621602
1210424302567b75
134959567b02151
141d2958931a369
15cae390317adb
hex642537a337c9

110111010011081 has 2 divisors, whose sum is σ = 110111010011082. Its totient is φ = 110111010011080.

The previous prime is 110111010011077. The next prime is 110111010011143. The reversal of 110111010011081 is 180110010111011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81813834010000 + 28297176001081 = 9045100^2 + 5319509^2 .

It is a cyclic number.

It is not a de Polignac number, because 110111010011081 - 22 = 110111010011077 is a prime.

It is a super-3 number, since 3×1101110100110813 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (110111010016081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055505005540 + 55055505005541.

It is an arithmetic number, because the mean of its divisors is an integer number (55055505005541).

Almost surely, 2110111010011081 is an apocalyptic number.

It is an amenable number.

110111010011081 is a deficient number, since it is larger than the sum of its proper divisors (1).

110111010011081 is an equidigital number, since it uses as much as digits as its factorization.

110111010011081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 17.

Adding to 110111010011081 its reverse (180110010111011), we get a palindrome (290221020122092).

The spelling of 110111010011081 in words is "one hundred ten trillion, one hundred eleven billion, ten million, eleven thousand, eighty-one".