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110111011000153 is a prime number
BaseRepresentation
bin11001000010010100110111…
…101100100100111101011001
3112102212111202200022212222021
4121002110313230210331121
5103413024322304001103
61030104144454454441
732123154333454402
oct3102246754447531
9472774680285867
10110111011000153
11320a28aa137719
1210424302964421
13495956808a3b7
141d295894d69a9
15cae390460bbd
hex642537b24f59

110111011000153 has 2 divisors, whose sum is σ = 110111011000154. Its totient is φ = 110111011000152.

The previous prime is 110111011000069. The next prime is 110111011000267. The reversal of 110111011000153 is 351000110111011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109474641038169 + 636369961984 = 10463013^2 + 797728^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110111011000153 is a prime.

It is not a weakly prime, because it can be changed into another prime (110111011000553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055505500076 + 55055505500077.

It is an arithmetic number, because the mean of its divisors is an integer number (55055505500077).

Almost surely, 2110111011000153 is an apocalyptic number.

It is an amenable number.

110111011000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

110111011000153 is an equidigital number, since it uses as much as digits as its factorization.

110111011000153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 16.

Adding to 110111011000153 its reverse (351000110111011), we get a palindrome (461111121111164).

The spelling of 110111011000153 in words is "one hundred ten trillion, one hundred eleven billion, eleven million, one hundred fifty-three", and thus it is an aban number.