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11011111000987 is a prime number
BaseRepresentation
bin1010000000111011100101…
…0111000001101110011011
31102222122121020222000021111
42200032321113001232123
52420401223404012422
635230233510521151
72214345411140236
oct240167127015633
942878536860244
1011011111000987
113565871112459
12129a03a9661b7
1361b460344556
142a0d2509c41d
15141656d72a77
hexa03b95c1b9b

11011111000987 has 2 divisors, whose sum is σ = 11011111000988. Its totient is φ = 11011111000986.

The previous prime is 11011111000979. The next prime is 11011111001053. The reversal of 11011111000987 is 78900011111011.

11011111000987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11011111000987 - 23 = 11011111000979 is a prime.

It is a super-2 number, since 2×110111110009872 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11011111000907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505555500493 + 5505555500494.

It is an arithmetic number, because the mean of its divisors is an integer number (5505555500494).

Almost surely, 211011111000987 is an apocalyptic number.

11011111000987 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011111000987 is an equidigital number, since it uses as much as digits as its factorization.

11011111000987 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 31.

Adding to 11011111000987 its reverse (78900011111011), we get a palindrome (89911122111998).

The spelling of 11011111000987 in words is "eleven trillion, eleven billion, one hundred eleven million, nine hundred eighty-seven", and thus it is an aban number.