Base | Representation |
---|---|
bin | 1010000000111011100101… |
… | …0111000100001110000011 |
3 | 1102222122121020222112021212 |
4 | 2200032321113010032003 |
5 | 2420401223404324303 |
6 | 35230233511040335 |
7 | 2214345411212102 |
oct | 240167127041603 |
9 | 42878536875255 |
10 | 11011111011203 |
11 | 356587111a0a6 |
12 | 129a03a9700ab |
13 | 61b4603490b4 |
14 | 2a0d250a2039 |
15 | 141656d75ad8 |
hex | a03b95c4383 |
11011111011203 has 2 divisors, whose sum is σ = 11011111011204. Its totient is φ = 11011111011202.
The previous prime is 11011111011181. The next prime is 11011111011223. The reversal of 11011111011203 is 30211011111011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11011111011203 - 232 = 11006816043907 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11011111011223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505555505601 + 5505555505602.
It is an arithmetic number, because the mean of its divisors is an integer number (5505555505602).
Almost surely, 211011111011203 is an apocalyptic number.
11011111011203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011111011203 is an equidigital number, since it uses as much as digits as its factorization.
11011111011203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 11011111011203 its reverse (30211011111011), we get a palindrome (41222122122214).
The spelling of 11011111011203 in words is "eleven trillion, eleven billion, one hundred eleven million, eleven thousand, two hundred three".
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