Base | Representation |
---|---|
bin | 10000000001011111111… |
… | …011010001011110111011 |
3 | 10220021012000102112120020 |
4 | 100001133323101132323 |
5 | 121020043434021103 |
6 | 2201503100301523 |
7 | 142360543040133 |
oct | 20013773213673 |
9 | 3807160375506 |
10 | 1101121001403 |
11 | 394a8a10aa35 |
12 | 1594a32418a3 |
13 | 7cab2100107 |
14 | 3b41a311ac3 |
15 | 1d9990d4753 |
hex | 1005fed17bb |
1101121001403 has 8 divisors (see below), whose sum is σ = 1495862492688. Its totient is φ = 720230088864.
The previous prime is 1101121001389. The next prime is 1101121001413. The reversal of 1101121001403 is 3041001211011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1101121001403 - 25 = 1101121001371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1101121001413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3462644500 + ... + 3462644817.
It is an arithmetic number, because the mean of its divisors is an integer number (186982811586).
Almost surely, 21101121001403 is an apocalyptic number.
1101121001403 is a deficient number, since it is larger than the sum of its proper divisors (394741491285).
1101121001403 is an equidigital number, since it uses as much as digits as its factorization.
1101121001403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6925289373.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 1101121001403 its reverse (3041001211011), we get a palindrome (4142122212414).
The spelling of 1101121001403 in words is "one trillion, one hundred one billion, one hundred twenty-one million, one thousand, four hundred three".
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