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1101121001403 = 3536925289317
BaseRepresentation
bin10000000001011111111…
…011010001011110111011
310220021012000102112120020
4100001133323101132323
5121020043434021103
62201503100301523
7142360543040133
oct20013773213673
93807160375506
101101121001403
11394a8a10aa35
121594a32418a3
137cab2100107
143b41a311ac3
151d9990d4753
hex1005fed17bb

1101121001403 has 8 divisors (see below), whose sum is σ = 1495862492688. Its totient is φ = 720230088864.

The previous prime is 1101121001389. The next prime is 1101121001413. The reversal of 1101121001403 is 3041001211011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1101121001403 - 25 = 1101121001371 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1101121001413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3462644500 + ... + 3462644817.

It is an arithmetic number, because the mean of its divisors is an integer number (186982811586).

Almost surely, 21101121001403 is an apocalyptic number.

1101121001403 is a deficient number, since it is larger than the sum of its proper divisors (394741491285).

1101121001403 is an equidigital number, since it uses as much as digits as its factorization.

1101121001403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6925289373.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1101121001403 its reverse (3041001211011), we get a palindrome (4142122212414).

The spelling of 1101121001403 in words is "one trillion, one hundred one billion, one hundred twenty-one million, one thousand, four hundred three".

Divisors: 1 3 53 159 6925289317 20775867951 367040333801 1101121001403