Base | Representation |
---|---|
bin | 11001000010010110101110… |
… | …011100101110011000001010 |
3 | 112102212200220112020220000112 |
4 | 121002112232130232120022 |
5 | 103413042412323130010 |
6 | 1030105114305234322 |
7 | 32123254605144350 |
oct | 3102265634563012 |
9 | 472780815226015 |
10 | 110113003333130 |
11 | 320a37318179a6 |
12 | 1042477a0329a2 |
13 | 49597c4a7ba55 |
14 | 1d296d7d577d0 |
15 | cae45a30ba05 |
hex | 6425ae72e60a |
110113003333130 has 16 divisors (see below), whose sum is σ = 226518178285440. Its totient is φ = 37753029714192.
The previous prime is 110113003333103. The next prime is 110113003333133. The reversal of 110113003333130 is 31333300311011.
It is a junction number, because it is equal to n+sod(n) for n = 110113003333096 and 110113003333105.
It is not an unprimeable number, because it can be changed into a prime (110113003333133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 786521452310 + ... + 786521452449.
It is an arithmetic number, because the mean of its divisors is an integer number (14157386142840).
Almost surely, 2110113003333130 is an apocalyptic number.
110113003333130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
110113003333130 is an abundant number, since it is smaller than the sum of its proper divisors (116405174952310).
110113003333130 is a wasteful number, since it uses less digits than its factorization.
110113003333130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1573042904773.
The product of its (nonzero) digits is 729, while the sum is 23.
Adding to 110113003333130 its reverse (31333300311011), we get a palindrome (141446303644141).
The spelling of 110113003333130 in words is "one hundred ten trillion, one hundred thirteen billion, three million, three hundred thirty-three thousand, one hundred thirty".
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