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1101131002013 = 7510130837959
BaseRepresentation
bin10000000001100000100…
…001011011000010011101
310220021012201020121211012
4100001200201123002131
5121020104014031023
62201504054505005
7142361024041340
oct20014041330235
93807181217735
101101131002013
11394a948205a9
121594a6665165
137cab41c2033
143b41b796457
151d999e0c978
hex1006085b09d

1101131002013 has 8 divisors (see below), whose sum is σ = 1258682175360. Its totient is φ = 943641514800.

The previous prime is 1101131002009. The next prime is 1101131002043. The reversal of 1101131002013 is 3102001311011.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1101131002013 - 22 = 1101131002009 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101131002043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15383273 + ... + 15454686.

It is an arithmetic number, because the mean of its divisors is an integer number (157335271920).

Almost surely, 21101131002013 is an apocalyptic number.

It is an amenable number.

1101131002013 is a deficient number, since it is larger than the sum of its proper divisors (157551173347).

1101131002013 is an equidigital number, since it uses as much as digits as its factorization.

1101131002013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30843067.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 1101131002013 its reverse (3102001311011), we get a palindrome (4203132313024).

The spelling of 1101131002013 in words is "one trillion, one hundred one billion, one hundred thirty-one million, two thousand, thirteen".

Divisors: 1 7 5101 35707 30837959 215865713 157304428859 1101131002013