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11011313281 is a prime number
BaseRepresentation
bin10100100000101001…
…10100111010000001
31001102101201200010211
422100110310322001
5140022344011111
65020350354121
7536604422113
oct122024647201
931371650124
1011011313281
114740665711
1221737bb941
131066388bb7
147665b73b3
15446a76521
hex290534e81

11011313281 has 2 divisors, whose sum is σ = 11011313282. Its totient is φ = 11011313280.

The previous prime is 11011313251. The next prime is 11011313317. The reversal of 11011313281 is 18231311011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10999814400 + 11498881 = 104880^2 + 3391^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11011313281 is a prime.

It is a super-2 number, since 2×110113132812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11011313251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505656640 + 5505656641.

It is an arithmetic number, because the mean of its divisors is an integer number (5505656641).

Almost surely, 211011313281 is an apocalyptic number.

It is an amenable number.

11011313281 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011313281 is an equidigital number, since it uses as much as digits as its factorization.

11011313281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 11011313281 its reverse (18231311011), we get a palindrome (29242624292).

The spelling of 11011313281 in words is "eleven billion, eleven million, three hundred thirteen thousand, two hundred eighty-one".