Search a number
-
+
11012002021020 = 223571113247774021
BaseRepresentation
bin1010000000111110111001…
…1101111111111010011100
31102222201220100120111222110
42200033232131333322130
52420410040004133040
635230502140314020
72214406450525260
oct240175635777234
942881810514873
1011012002021020
113566189070a50
12129a249242910
1361b572b15740
142a0dab55c0a0
151416aa1c8980
hexa03ee77fe9c

11012002021020 has 384 divisors, whose sum is σ = 41416239900672. Its totient is φ = 2111310950400.

The previous prime is 11012002020989. The next prime is 11012002021099. The reversal of 11012002021020 is 2012020021011.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 11012002020987 and 11012002021005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 148731610 + ... + 148805630.

It is an arithmetic number, because the mean of its divisors is an integer number (107854791408).

Almost surely, 211012002021020 is an apocalyptic number.

11012002021020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11012002021020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20708119950336).

11012002021020 is an abundant number, since it is smaller than the sum of its proper divisors (30404237879652).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11012002021020 is a wasteful number, since it uses less digits than its factorization.

11012002021020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76541 (or 76539 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 12.

Adding to 11012002021020 its reverse (2012020021011), we get a palindrome (13024022042031).

Subtracting from 11012002021020 its reverse (2012020021011), we obtain a square (8999982000009 = 29999972).

The spelling of 11012002021020 in words is "eleven trillion, twelve billion, two million, twenty-one thousand, twenty".