Base | Representation |
---|---|
bin | 11001000010011101100011… |
… | …010110110011100110011111 |
3 | 112102220101211101010010210122 |
4 | 121002131203112303212133 |
5 | 103413202420324100210 |
6 | 1030112325514425155 |
7 | 32123634342663632 |
oct | 3102354326634637 |
9 | 472811741103718 |
10 | 110120333425055 |
11 | 320a6853429508 |
12 | 10426084a321bb |
13 | 495a3c258a555 |
14 | 1d29bd167bc19 |
15 | cae738acab55 |
hex | 6427635b399f |
110120333425055 has 16 divisors (see below), whose sum is σ = 135383622835104. Its totient is φ = 85937298846720.
The previous prime is 110120333425019. The next prime is 110120333425057. The reversal of 110120333425055 is 550524333021011.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-110120333425055 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110120333425057) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30401594 + ... + 33830423.
It is an arithmetic number, because the mean of its divisors is an integer number (8461476427194).
Almost surely, 2110120333425055 is an apocalyptic number.
110120333425055 is a deficient number, since it is larger than the sum of its proper divisors (25263289410049).
110120333425055 is an equidigital number, since it uses as much as digits as its factorization.
110120333425055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64240426.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 110120333425055 its reverse (550524333021011), we get a palindrome (660644666446066).
The spelling of 110120333425055 in words is "one hundred ten trillion, one hundred twenty billion, three hundred thirty-three million, four hundred twenty-five thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •