Base | Representation |
---|---|
bin | 10000000001100101001… |
… | …111100010110010010001 |
3 | 10220021102020021100201122 |
4 | 100001211033202302101 |
5 | 121020234302414413 |
6 | 2201520004212025 |
7 | 142363005161012 |
oct | 20014517426221 |
9 | 3807366240648 |
10 | 1101210201233 |
11 | 3950254a50aa |
12 | 15950909a015 |
13 | 7cac7731a8c |
14 | 3b4280d1009 |
15 | 1d9a1d54108 |
hex | 100653e2c91 |
1101210201233 has 2 divisors, whose sum is σ = 1101210201234. Its totient is φ = 1101210201232.
The previous prime is 1101210201193. The next prime is 1101210201307. The reversal of 1101210201233 is 3321020121011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 958965815824 + 142244385409 = 979268^2 + 377153^2 .
It is an emirp because it is prime and its reverse (3321020121011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1101210201233 - 28 = 1101210200977 is a prime.
It is not a weakly prime, because it can be changed into another prime (1101210204233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550605100616 + 550605100617.
It is an arithmetic number, because the mean of its divisors is an integer number (550605100617).
Almost surely, 21101210201233 is an apocalyptic number.
It is an amenable number.
1101210201233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101210201233 is an equidigital number, since it uses as much as digits as its factorization.
1101210201233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1101210201233 its reverse (3321020121011), we get a palindrome (4422230322244).
The spelling of 1101210201233 in words is "one trillion, one hundred one billion, two hundred ten million, two hundred one thousand, two hundred thirty-three".
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