Base | Representation |
---|---|
bin | 1010000000111111010011… |
… | …1110100011110111000011 |
3 | 1102222202011222001102001011 |
4 | 2200033310332203313003 |
5 | 2420410300433021123 |
6 | 35230521041021351 |
7 | 2214412244643154 |
oct | 240176476436703 |
9 | 42882158042034 |
10 | 11012111220163 |
11 | 3566234775979 |
12 | 129a279924857 |
13 | 61b58c62a411 |
14 | 2a0dbbc6592b |
15 | 1416b4a98e0d |
hex | a03f4fa3dc3 |
11012111220163 has 2 divisors, whose sum is σ = 11012111220164. Its totient is φ = 11012111220162.
The previous prime is 11012111220079. The next prime is 11012111220221. The reversal of 11012111220163 is 36102211121011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11012111220163 is a prime.
It is not a weakly prime, because it can be changed into another prime (11012111227163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506055610081 + 5506055610082.
It is an arithmetic number, because the mean of its divisors is an integer number (5506055610082).
Almost surely, 211012111220163 is an apocalyptic number.
11012111220163 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012111220163 is an equidigital number, since it uses as much as digits as its factorization.
11012111220163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 11012111220163 its reverse (36102211121011), we get a palindrome (47114322341174).
The spelling of 11012111220163 in words is "eleven trillion, twelve billion, one hundred eleven million, two hundred twenty thousand, one hundred sixty-three".
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