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11012112012000 = 2535311101825991
BaseRepresentation
bin1010000000111111010100…
…0001100101001011100000
31102222202012000112122020110
42200033311001211023200
52420410301133341000
635230521110011320
72214412254451551
oct240176501451340
942882160478213
1011012112012000
113566235166890
12129a27a046b40
1361b58c846968
142a0dbbdd0328
151416b4ba3850
hexa03f50652e0

11012112012000 has 384 divisors, whose sum is σ = 39744990544896. Its totient is φ = 2643168000000.

The previous prime is 11012112011987. The next prime is 11012112012053. The reversal of 11012112012000 is 21021121011.

It is a super-2 number, since 2×110121120120002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12919005 + ... + 13744995.

It is an arithmetic number, because the mean of its divisors is an integer number (103502579544).

Almost surely, 211012112012000 is an apocalyptic number.

11012112012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11012112012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19872495272448).

11012112012000 is an abundant number, since it is smaller than the sum of its proper divisors (28732878532896).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11012112012000 is a wasteful number, since it uses less digits than its factorization.

11012112012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 826131 (or 826113 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 11012112012000 its reverse (21021121011), we get a palindrome (11033133133011).

It can be divided in two parts, 110121 and 12012000, that added together give a palindrome (12122121).

The spelling of 11012112012000 in words is "eleven trillion, twelve billion, one hundred twelve million, twelve thousand".