Base | Representation |
---|---|
bin | 1010000000111111010110… |
… | …0110001011000111000111 |
3 | 1102222202012200120222202010 |
4 | 2200033311212023013013 |
5 | 2420410311112321201 |
6 | 35230522051345303 |
7 | 2214412432133304 |
oct | 240176546130707 |
9 | 42882180528663 |
10 | 11012121604551 |
11 | 356623a618911 |
12 | 129a2812b2233 |
13 | 61b591824c22 |
14 | 2a0dbd3aa0ab |
15 | 1416b594abd6 |
hex | a03f598b1c7 |
11012121604551 has 16 divisors (see below), whose sum is σ = 14706360919040. Its totient is φ = 7329655033920.
The previous prime is 11012121604493. The next prime is 11012121604559. The reversal of 11012121604551 is 15540612121011.
11012121604551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11012121604551 - 215 = 11012121571783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012121604559) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5766570 + ... + 7434888.
It is an arithmetic number, because the mean of its divisors is an integer number (919147557440).
Almost surely, 211012121604551 is an apocalyptic number.
11012121604551 is a deficient number, since it is larger than the sum of its proper divisors (3694239314489).
11012121604551 is a wasteful number, since it uses less digits than its factorization.
11012121604551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1671846.
The product of its (nonzero) digits is 2400, while the sum is 30.
Adding to 11012121604551 its reverse (15540612121011), we get a palindrome (26552733725562).
The spelling of 11012121604551 in words is "eleven trillion, twelve billion, one hundred twenty-one million, six hundred four thousand, five hundred fifty-one".
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