Base | Representation |
---|---|
bin | 1010000000111111101001… |
… | …0110010001101011100010 |
3 | 1102222202102020121010012221 |
4 | 2200033322112101223202 |
5 | 2420410442014320414 |
6 | 35230534020141254 |
7 | 2214414420545266 |
oct | 240177226215342 |
9 | 42882366533187 |
10 | 11012201323234 |
11 | 3566280617721 |
12 | 129a2a3b3782a |
13 | 61b5a51b7247 |
14 | 2a0dc9bdc0a6 |
15 | 1416bc946224 |
hex | a03fa591ae2 |
11012201323234 has 4 divisors (see below), whose sum is σ = 16518301984854. Its totient is φ = 5506100661616.
The previous prime is 11012201323231. The next prime is 11012201323243. The reversal of 11012201323234 is 43232310221011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9089000951209 + 1923200372025 = 3014797^2 + 1386795^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11012201323199 and 11012201323208.
It is not an unprimeable number, because it can be changed into a prime (11012201323231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2753050330807 + ... + 2753050330810.
Almost surely, 211012201323234 is an apocalyptic number.
11012201323234 is a deficient number, since it is larger than the sum of its proper divisors (5506100661620).
11012201323234 is an equidigital number, since it uses as much as digits as its factorization.
11012201323234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5506100661619.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11012201323234 its reverse (43232310221011), we get a palindrome (54244511544245).
The spelling of 11012201323234 in words is "eleven trillion, twelve billion, two hundred one million, three hundred twenty-three thousand, two hundred thirty-four".
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