Base | Representation |
---|---|
bin | 1010000000111111101011… |
… | …1011111111111101111001 |
3 | 1102222202102221012112021012 |
4 | 2200033322323333331321 |
5 | 2420411002032242103 |
6 | 35230535012123305 |
7 | 2214414600603044 |
oct | 240177273777571 |
9 | 42882387175235 |
10 | 11012211212153 |
11 | 3566286161388 |
12 | 129a2a7306535 |
13 | 61b5a726a388 |
14 | 2a0dcb253c5b |
15 | 1416bd74b2d8 |
hex | a03faefff79 |
11012211212153 has 2 divisors, whose sum is σ = 11012211212154. Its totient is φ = 11012211212152.
The previous prime is 11012211212111. The next prime is 11012211212201. The reversal of 11012211212153 is 35121211221011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5723328953104 + 5288882259049 = 2392348^2 + 2299757^2 .
It is a cyclic number.
It is not a de Polignac number, because 11012211212153 - 26 = 11012211212089 is a prime.
It is not a weakly prime, because it can be changed into another prime (11012211212053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506105606076 + 5506105606077.
It is an arithmetic number, because the mean of its divisors is an integer number (5506105606077).
Almost surely, 211012211212153 is an apocalyptic number.
It is an amenable number.
11012211212153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012211212153 is an equidigital number, since it uses as much as digits as its factorization.
11012211212153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 11012211212153 its reverse (35121211221011), we get a palindrome (46133422433164).
The spelling of 11012211212153 in words is "eleven trillion, twelve billion, two hundred eleven million, two hundred twelve thousand, one hundred fifty-three".
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