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1101221320123 is a prime number
BaseRepresentation
bin10000000001100101111…
…001111101010110111011
310220021110000012020222101
4100001211321331112323
5121020300124220443
62201521042404231
7142363201530421
oct20014571752673
93807400166871
101101221320123
113950307a9971
12159510960677
137cac9b259c2
143b429787111
151d9a2ced84d
hex10065e7d5bb

1101221320123 has 2 divisors, whose sum is σ = 1101221320124. Its totient is φ = 1101221320122.

The previous prime is 1101221320109. The next prime is 1101221320153. The reversal of 1101221320123 is 3210231221011.

It is a weak prime.

It is an emirp because it is prime and its reverse (3210231221011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101221320123 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1101221320123.

It is not a weakly prime, because it can be changed into another prime (1101221320103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550610660061 + 550610660062.

It is an arithmetic number, because the mean of its divisors is an integer number (550610660062).

Almost surely, 21101221320123 is an apocalyptic number.

1101221320123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101221320123 is an equidigital number, since it uses as much as digits as its factorization.

1101221320123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1101221320123 its reverse (3210231221011), we get a palindrome (4311452541134).

The spelling of 1101221320123 in words is "one trillion, one hundred one billion, two hundred twenty-one million, three hundred twenty thousand, one hundred twenty-three".