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11012218433 is a prime number
BaseRepresentation
bin10100100000110000…
…10001111001000001
31001102110102122202222
422100120101321001
5140023111442213
65020422020425
7536615212046
oct122030217101
931373378688
1011012218433
114741123777
122173b77715
131066614ba8
147667711cd
15446ba4808
hex290611e41

11012218433 has 2 divisors, whose sum is σ = 11012218434. Its totient is φ = 11012218432.

The previous prime is 11012218391. The next prime is 11012218447. The reversal of 11012218433 is 33481221011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10748090929 + 264127504 = 103673^2 + 16252^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012218433 - 220 = 11011169857 is a prime.

It is a super-2 number, since 2×110122184332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11012218033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506109216 + 5506109217.

It is an arithmetic number, because the mean of its divisors is an integer number (5506109217).

Almost surely, 211012218433 is an apocalyptic number.

It is an amenable number.

11012218433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012218433 is an equidigital number, since it uses as much as digits as its factorization.

11012218433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 11012218433 its reverse (33481221011), we get a palindrome (44493439444).

The spelling of 11012218433 in words is "eleven billion, twelve million, two hundred eighteen thousand, four hundred thirty-three".