Base | Representation |
---|---|
bin | 10100100000110000… |
… | …10001111001000001 |
3 | 1001102110102122202222 |
4 | 22100120101321001 |
5 | 140023111442213 |
6 | 5020422020425 |
7 | 536615212046 |
oct | 122030217101 |
9 | 31373378688 |
10 | 11012218433 |
11 | 4741123777 |
12 | 2173b77715 |
13 | 1066614ba8 |
14 | 7667711cd |
15 | 446ba4808 |
hex | 290611e41 |
11012218433 has 2 divisors, whose sum is σ = 11012218434. Its totient is φ = 11012218432.
The previous prime is 11012218391. The next prime is 11012218447. The reversal of 11012218433 is 33481221011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10748090929 + 264127504 = 103673^2 + 16252^2 .
It is a cyclic number.
It is not a de Polignac number, because 11012218433 - 220 = 11011169857 is a prime.
It is a super-2 number, since 2×110122184332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11012218033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506109216 + 5506109217.
It is an arithmetic number, because the mean of its divisors is an integer number (5506109217).
Almost surely, 211012218433 is an apocalyptic number.
It is an amenable number.
11012218433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012218433 is an equidigital number, since it uses as much as digits as its factorization.
11012218433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 11012218433 its reverse (33481221011), we get a palindrome (44493439444).
The spelling of 11012218433 in words is "eleven billion, twelve million, two hundred eighteen thousand, four hundred thirty-three".
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