Base | Representation |
---|---|
bin | 11001000010100000000010… |
… | …111001111001001000110000 |
3 | 112102220122201220221101212120 |
4 | 121002200002321321020300 |
5 | 103413223411102400422 |
6 | 1030113451255154240 |
7 | 32124060565126560 |
oct | 3102400271711060 |
9 | 472818656841776 |
10 | 110123010200112 |
11 | 320a79a73a21a8 |
12 | 104266b1375980 |
13 | 495a72b001a10 |
14 | 1d29da6d86da0 |
15 | cae843ac445c |
hex | 642802e79230 |
110123010200112 has 640 divisors, whose sum is σ = 364158356373504. Its totient is φ = 27901843697664.
The previous prime is 110123010200087. The next prime is 110123010200117. The reversal of 110123010200112 is 211002010321011.
It is a junction number, because it is equal to n+sod(n) for n = 110123010200091 and 110123010200100.
It is not an unprimeable number, because it can be changed into a prime (110123010200117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 5308913613 + ... + 5308934355.
Almost surely, 2110123010200112 is an apocalyptic number.
110123010200112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 110123010200112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (182079178186752).
110123010200112 is an abundant number, since it is smaller than the sum of its proper divisors (254035346173392).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110123010200112 is a wasteful number, since it uses less digits than its factorization.
110123010200112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21225 (or 21219 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 110123010200112 its reverse (211002010321011), we get a palindrome (321125020521123).
The spelling of 110123010200112 in words is "one hundred ten trillion, one hundred twenty-three billion, ten million, two hundred thousand, one hundred twelve".
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