Base | Representation |
---|---|
bin | 1010000001000000000001… |
… | …0110010101110011101001 |
3 | 1102222202200021001012111012 |
4 | 2200100000112111303221 |
5 | 2420411143303102213 |
6 | 35230552014113305 |
7 | 2214420052402463 |
oct | 240200026256351 |
9 | 42882607035435 |
10 | 11012302003433 |
11 | 35663224331a5 |
12 | 129a3117ab835 |
13 | 61b5c0008523 |
14 | 2a0dd9329133 |
15 | 1416c66d24a8 |
hex | a0400595ce9 |
11012302003433 has 2 divisors, whose sum is σ = 11012302003434. Its totient is φ = 11012302003432.
The previous prime is 11012302003397. The next prime is 11012302003457. The reversal of 11012302003433 is 33430020321011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7818046589929 + 3194255413504 = 2796077^2 + 1787248^2 .
It is a cyclic number.
It is not a de Polignac number, because 11012302003433 - 238 = 10737424096489 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11012302003399 and 11012302003408.
It is not a weakly prime, because it can be changed into another prime (11012302003033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506151001716 + 5506151001717.
It is an arithmetic number, because the mean of its divisors is an integer number (5506151001717).
Almost surely, 211012302003433 is an apocalyptic number.
It is an amenable number.
11012302003433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012302003433 is an equidigital number, since it uses as much as digits as its factorization.
11012302003433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11012302003433 its reverse (33430020321011), we get a palindrome (44442322324444).
The spelling of 11012302003433 in words is "eleven trillion, twelve billion, three hundred two million, three thousand, four hundred thirty-three".
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