Base | Representation |
---|---|
bin | 1010000001000000000001… |
… | …1000010100110010011111 |
3 | 1102222202200022000121221211 |
4 | 2200100000120110302133 |
5 | 2420411143421223201 |
6 | 35230552033205251 |
7 | 2214420060000040 |
oct | 240200030246237 |
9 | 42882608017854 |
10 | 11012302523551 |
11 | 3566322758a4a |
12 | 129a311a00827 |
13 | 61b5c015b1a4 |
14 | 2a0dd94228c7 |
15 | 1416c6786651 |
hex | a0400614c9f |
11012302523551 has 4 divisors (see below), whose sum is σ = 12585488598352. Its totient is φ = 9439116448752.
The previous prime is 11012302523489. The next prime is 11012302523603. The reversal of 11012302523551 is 15532520321011.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11012302523551 - 29 = 11012302523039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012302503551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786593037390 + ... + 786593037403.
It is an arithmetic number, because the mean of its divisors is an integer number (3146372149588).
Almost surely, 211012302523551 is an apocalyptic number.
11012302523551 is a deficient number, since it is larger than the sum of its proper divisors (1573186074801).
11012302523551 is an equidigital number, since it uses as much as digits as its factorization.
11012302523551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1573186074800.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 11012302523551 its reverse (15532520321011), we get a palindrome (26544822844562).
The spelling of 11012302523551 in words is "eleven trillion, twelve billion, three hundred two million, five hundred twenty-three thousand, five hundred fifty-one".
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