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1101240145121 is a prime number
BaseRepresentation
bin10000000001100111000…
…001110001010011100001
310220021111022121200000112
4100001213001301103201
5121020314434120441
62201522554101105
7142363520533664
oct20014701612341
93807438550015
101101240145121
11395040397416
1215951711a795
137cb009b735c
143b42c0876db
151d9a47bb4eb
hex100670714e1

1101240145121 has 2 divisors, whose sum is σ = 1101240145122. Its totient is φ = 1101240145120.

The previous prime is 1101240145097. The next prime is 1101240145127. The reversal of 1101240145121 is 1215410421011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 881570766400 + 219669378721 = 938920^2 + 468689^2 .

It is an emirp because it is prime and its reverse (1215410421011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1101240145121 - 210 = 1101240144097 is a prime.

It is a super-2 number, since 2×11012401451212 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1101240145127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550620072560 + 550620072561.

It is an arithmetic number, because the mean of its divisors is an integer number (550620072561).

Almost surely, 21101240145121 is an apocalyptic number.

It is an amenable number.

1101240145121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101240145121 is an equidigital number, since it uses as much as digits as its factorization.

1101240145121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 320, while the sum is 23.

Adding to 1101240145121 its reverse (1215410421011), we get a palindrome (2316650566132).

The spelling of 1101240145121 in words is "one trillion, one hundred one billion, two hundred forty million, one hundred forty-five thousand, one hundred twenty-one".