11012442240053 has 4 divisors (see below), whose sum is σ = 11027263831968. Its totient is φ = 10997620648140.

The previous prime is 11012442240047. The next prime is 11012442240067. The reversal of 11012442240053 is 35004224421011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11012442240053 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11012442239998 and 11012442240025.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11012442240043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7410794843 + ... + 7410796328.

It is an arithmetic number, because the mean of its divisors is an integer number (2756815957992).

Almost surely, 2^{11012442240053} is an apocalyptic number.

It is an amenable number.

11012442240053 is a deficient number, since it is larger than the sum of its proper divisors (14821591915).

11012442240053 is an equidigital number, since it uses as much as digits as its factorization.

11012442240053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14821591914.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 11012442240053 its reverse (35004224421011), we get a palindrome (46016666661064).

The spelling of 11012442240053 in words is "eleven trillion, twelve billion, four hundred forty-two million, two hundred forty thousand, fifty-three".