110130000403 has 2 divisors, whose sum is σ = 110130000404. Its totient is φ = 110130000402.

The previous prime is 110130000391. The next prime is 110130000437. The reversal of 110130000403 is 304000031011.

It is a weak prime.

It is an emirp because it is prime and its reverse (304000031011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110130000403 - 2⁹ = 110129999891 is a prime.

It is not a weakly prime, because it can be changed into another prime (110130000503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55065000201 + 55065000202.

It is an arithmetic number, because the mean of its divisors is an integer number (55065000202).

Almost surely, 2^110130000403 is an apocalyptic number.

110130000403 is a deficient number, since it is larger than the sum of its proper divisors (1).

110130000403 is an equidigital number, since it uses as much as digits as its factorization.

110130000403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 110130000403 its reverse (304000031011), we get a palindrome (414130031414).

The spelling of 110130000403 in words is "one hundred ten billion, one hundred thirty million, four hundred three", and thus it is an aban number.