Base | Representation |
---|---|
bin | 10000000001101010100… |
… | …111010111101000101001 |
3 | 10220021122111212112101211 |
4 | 100001222213113220221 |
5 | 121020430341124342 |
6 | 2201532544113121 |
7 | 142365151243066 |
oct | 20015247275051 |
9 | 3807574775354 |
10 | 1101300333097 |
11 | 395071366548 |
12 | 1595333057a1 |
13 | 7cb102cba43 |
14 | 3b436073c6d |
15 | 1d9a9c09c17 |
hex | 1006a9d7a29 |
1101300333097 has 2 divisors, whose sum is σ = 1101300333098. Its totient is φ = 1101300333096.
The previous prime is 1101300333019. The next prime is 1101300333121. The reversal of 1101300333097 is 7903330031011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 689449569561 + 411850763536 = 830331^2 + 641756^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101300333097 - 215 = 1101300300329 is a prime.
It is a super-2 number, since 2×11013003330972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1101300333017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550650166548 + 550650166549.
It is an arithmetic number, because the mean of its divisors is an integer number (550650166549).
Almost surely, 21101300333097 is an apocalyptic number.
It is an amenable number.
1101300333097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101300333097 is an equidigital number, since it uses as much as digits as its factorization.
1101300333097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5103, while the sum is 31.
The spelling of 1101300333097 in words is "one trillion, one hundred one billion, three hundred million, three hundred thirty-three thousand, ninety-seven".
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