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110130313103 = 131840689413
BaseRepresentation
bin110011010010001000…
…1110011011110001111
3101112021011121120100022
41212210101303132033
53301021330004403
6122332042452355
710646063134016
oct1464421633617
9345234546308
10110130313103
1142784766298
12194165040bb
13a5014c5055
14548a625a7d
152ce8788d38
hex19a447378f

110130313103 has 4 divisors (see below), whose sum is σ = 110971002648. Its totient is φ = 109289623560.

The previous prime is 110130313093. The next prime is 110130313243. The reversal of 110130313103 is 301313031011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301313031011 = 1795916777829.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110130313103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110130313303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 420344576 + ... + 420344837.

It is an arithmetic number, because the mean of its divisors is an integer number (27742750662).

Almost surely, 2110130313103 is an apocalyptic number.

110130313103 is a deficient number, since it is larger than the sum of its proper divisors (840689545).

110130313103 is an equidigital number, since it uses as much as digits as its factorization.

110130313103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 840689544.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 110130313103 its reverse (301313031011), we get a palindrome (411443344114).

The spelling of 110130313103 in words is "one hundred ten billion, one hundred thirty million, three hundred thirteen thousand, one hundred three".

Divisors: 1 131 840689413 110130313103