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11013033131100 = 22325271113175571291
BaseRepresentation
bin1010000001000010101111…
…1011010111110001011100
31102222211120012210100002200
42200100223323113301130
52420414142440143400
635231152332451500
72214444141030150
oct240205373276134
942884505710080
1011013033131100
113566668103240
12129a496619b90
1361b6a8625c50
142a1068487060
1514171a9a2b00
hexa042bed7c5c

11013033131100 has 1728 divisors, whose sum is σ = 49200732951552. Its totient is φ = 1983025152000.

The previous prime is 11013033131063. The next prime is 11013033131137. The reversal of 11013033131100 is 113133031011.

11013033131100 is a `hidden beast` number, since 1 + 10 + 13 + 0 + 331 + 311 + 0 + 0 = 666.

11013033131100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11013033131063) and next prime (11013033131137).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 575 ways as a sum of consecutive naturals, for example, 8530621455 + ... + 8530622745.

It is an arithmetic number, because the mean of its divisors is an integer number (28472646384).

Almost surely, 211013033131100 is an apocalyptic number.

11013033131100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11013033131100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24600366475776).

11013033131100 is an abundant number, since it is smaller than the sum of its proper divisors (38187699820452).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11013033131100 is a wasteful number, since it uses less digits than its factorization.

11013033131100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1916 (or 1906 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 11013033131100 its reverse (113133031011), we get a palindrome (11126166162111).

The spelling of 11013033131100 in words is "eleven trillion, thirteen billion, thirty-three million, one hundred thirty-one thousand, one hundred".