11013043431 has 16 divisors (see below), whose sum is σ = 16150063104. Its totient is φ = 6633059424.

The previous prime is 11013043421. The next prime is 11013043441. The reversal of 11013043431 is 13434031011.

It is an interprime number because it is at equal distance from previous prime (11013043421) and next prime (11013043441).

It is not a de Polignac number, because 11013043431 - 2¹³ = 11013035239 is a prime.

It is a super-2 number, since 2×11013043431² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11013043398 and 11013043407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013043421) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3002271 + ... + 3005936.

It is an arithmetic number, because the mean of its divisors is an integer number (1009378944).

Almost surely, 2^11013043431 is an apocalyptic number.

11013043431 is a deficient number, since it is larger than the sum of its proper divisors (5137019673).

11013043431 is a wasteful number, since it uses less digits than its factorization.

11013043431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6008270.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11013043431 its reverse (13434031011), we get a palindrome (24447074442).

The spelling of 11013043431 in words is "eleven billion, thirteen million, forty-three thousand, four hundred thirty-one".