1101312019 has 2 divisors, whose sum is σ = 1101312020. Its totient is φ = 1101312018.

The previous prime is 1101311941. The next prime is 1101312049. The reversal of 1101312019 is 9102131011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1101312019 - 2¹⁹ = 1100787731 is a prime.

It is a super-2 number, since 2×1101312019² = 2425776326387712722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1101311987 and 1101312005.

It is not a weakly prime, because it can be changed into another prime (1101312049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550656009 + 550656010.

It is an arithmetic number, because the mean of its divisors is an integer number (550656010).

Almost surely, 2^1101312019 is an apocalyptic number.

1101312019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101312019 is an equidigital number, since it uses as much as digits as its factorization.

1101312019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

The square root of 1101312019 is about 33186.0214397568. The cubic root of 1101312019 is about 1032.6903678832.

It can be divided in two parts, 11013 and 12019, that added together give a palindrome (23032).

The spelling of 1101312019 in words is "one billion, one hundred one million, three hundred twelve thousand, nineteen".