Base | Representation |
---|---|
bin | 1010000001000011000100… |
… | …1011010111011111011011 |
3 | 1102222211210100112020002102 |
4 | 2200100301023113133123 |
5 | 2420414333012212311 |
6 | 35231205200354015 |
7 | 2214446260503002 |
oct | 240206113273733 |
9 | 42884710466072 |
10 | 11013121210331 |
11 | 35667028a2499 |
12 | 129a50001590b |
13 | 61b6c0954836 |
14 | 2a1076053c39 |
15 | 1417235a043b |
hex | a04312d77db |
11013121210331 has 2 divisors, whose sum is σ = 11013121210332. Its totient is φ = 11013121210330.
The previous prime is 11013121210307. The next prime is 11013121210373. The reversal of 11013121210331 is 13301212131011.
11013121210331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11013121210331 is a prime.
It is a super-2 number, since 2×110131212103312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11013121210381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506560605165 + 5506560605166.
It is an arithmetic number, because the mean of its divisors is an integer number (5506560605166).
Almost surely, 211013121210331 is an apocalyptic number.
11013121210331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013121210331 is an equidigital number, since it uses as much as digits as its factorization.
11013121210331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 11013121210331 its reverse (13301212131011), we get a palindrome (24314333341342).
The spelling of 11013121210331 in words is "eleven trillion, thirteen billion, one hundred twenty-one million, two hundred ten thousand, three hundred thirty-one".
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