Base | Representation |
---|---|
bin | 10100100000110111… |
… | …01110010011011001 |
3 | 1001102112010112012022 |
4 | 22100123232103121 |
5 | 140023324334431 |
6 | 5020453224225 |
7 | 536625662123 |
oct | 122033562331 |
9 | 31375115168 |
10 | 11013121241 |
11 | 474168aaa1 |
12 | 2174332075 |
13 | 106686cab5 |
14 | 766928213 |
15 | 446cd207b |
hex | 2906ee4d9 |
11013121241 has 2 divisors, whose sum is σ = 11013121242. Its totient is φ = 11013121240.
The previous prime is 11013121201. The next prime is 11013121337. The reversal of 11013121241 is 14212131011.
11013121241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7412521216 + 3600600025 = 86096^2 + 60005^2 .
It is a cyclic number.
It is not a de Polignac number, because 11013121241 - 26 = 11013121177 is a prime.
It is not a weakly prime, because it can be changed into another prime (11013121201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506560620 + 5506560621.
It is an arithmetic number, because the mean of its divisors is an integer number (5506560621).
Almost surely, 211013121241 is an apocalyptic number.
It is an amenable number.
11013121241 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013121241 is an equidigital number, since it uses as much as digits as its factorization.
11013121241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11013121241 its reverse (14212131011), we get a palindrome (25225252252).
The spelling of 11013121241 in words is "eleven billion, thirteen million, one hundred twenty-one thousand, two hundred forty-one".
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