Base | Representation |
---|---|
bin | 11001000010100111101100… |
… | …010111011011000110000011 |
3 | 112102221102221012220001121021 |
4 | 121002213230113123012003 |
5 | 103413342220313000003 |
6 | 1030121330202410311 |
7 | 32124501230231251 |
oct | 3102475427330603 |
9 | 472842835801537 |
10 | 110131222000003 |
11 | 32100430781a86 |
12 | 10428203500997 |
13 | 495b4393a0cc9 |
14 | 1d2a5458255d1 |
15 | caeb749aa2bd |
hex | 6429ec5db183 |
110131222000003 has 2 divisors, whose sum is σ = 110131222000004. Its totient is φ = 110131222000002.
The previous prime is 110131221999989. The next prime is 110131222000021. The reversal of 110131222000003 is 300000222131011.
It is a weak prime.
It is an emirp because it is prime and its reverse (300000222131011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110131222000003 - 225 = 110131188445571 is a prime.
It is not a weakly prime, because it can be changed into another prime (110131222000103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55065611000001 + 55065611000002.
It is an arithmetic number, because the mean of its divisors is an integer number (55065611000002).
Almost surely, 2110131222000003 is an apocalyptic number.
110131222000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
110131222000003 is an equidigital number, since it uses as much as digits as its factorization.
110131222000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 110131222000003 its reverse (300000222131011), we get a palindrome (410131444131014).
The spelling of 110131222000003 in words is "one hundred ten trillion, one hundred thirty-one billion, two hundred twenty-two million, three", and thus it is an aban number.
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