Base | Representation |
---|---|
bin | 1010000001000011001001… |
… | …1100100110101110100011 |
3 | 1102222211211211121011210211 |
4 | 2200100302130212232203 |
5 | 2420414403440201103 |
6 | 35231211241034551 |
7 | 2214446636510452 |
oct | 240206234465643 |
9 | 42884754534724 |
10 | 11013142506403 |
11 | 3566713918554 |
12 | 129a507185a57 |
13 | 61b6c519cb6b |
14 | 2a1078bd8b99 |
15 | 1417253aa36d |
hex | a0432726ba3 |
11013142506403 has 2 divisors, whose sum is σ = 11013142506404. Its totient is φ = 11013142506402.
The previous prime is 11013142506371. The next prime is 11013142506427. The reversal of 11013142506403 is 30460524131011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11013142506403 - 25 = 11013142506371 is a prime.
It is not a weakly prime, because it can be changed into another prime (11013142506433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506571253201 + 5506571253202.
It is an arithmetic number, because the mean of its divisors is an integer number (5506571253202).
Almost surely, 211013142506403 is an apocalyptic number.
11013142506403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013142506403 is an equidigital number, since it uses as much as digits as its factorization.
11013142506403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 11013142506403 its reverse (30460524131011), we get a palindrome (41473666637414).
The spelling of 11013142506403 in words is "eleven trillion, thirteen billion, one hundred forty-two million, five hundred six thousand, four hundred three".
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